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Diff for /loncom/interface/lonnavmaps.pm between versions 1.192 and 1.193

version 1.192, 2003/05/16 17:54:21 version 1.193, 2003/05/27 21:00:23
Line 1662  sub init { Line 1662  sub init {
         my %emailstatus = &Apache::lonnet::dump('email_status');          my %emailstatus = &Apache::lonnet::dump('email_status');
         my $logoutTime = $emailstatus{'logout'};          my $logoutTime = $emailstatus{'logout'};
         my $courseLeaveTime = $emailstatus{'logout_'.$ENV{'request.course.id'}};          my $courseLeaveTime = $emailstatus{'logout_'.$ENV{'request.course.id'}};
         $self->{LAST_CHECK} = ($courseLeaveTime < $logoutTime ?          $self->{LAST_CHECK} = (($courseLeaveTime > $logoutTime) ?
                                $courseLeaveTime : $logoutTime);                                 $courseLeaveTime : $logoutTime);
         my %discussiontime = &Apache::lonnet::dump('discussiontimes',           my %discussiontime = &Apache::lonnet::dump('discussiontimes', 
                                                    $cdom, $cnum);                                                     $cdom, $cnum);
Line 3211  sub getErrors { Line 3211  sub getErrors {
 =item * B<parts>():  =item * B<parts>():
   
 Returns a list reference containing sorted strings corresponding to  Returns a list reference containing sorted strings corresponding to
 each part of the problem. To count the number of parts, use the list  each part of the problem. Single part problems have only a part '0'.
 in a scalar context, and subtract one if greater than two. (One part  Multipart problems do not return their part '0', since they typically
 problems have a part 0. Multi-parts have a part 0, plus a part for  do not really matter. 
 each part. Filtering part 0 if you want it is up to you.)  
   
 =item * B<countParts>():  =item * B<countParts>():
   
 Returns the number of parts of the problem a student can answer. Thus,  Returns the number of parts of the problem a student can answer. Thus,
 for single part problems, returns 1. For multipart, it returns the  for single part problems, returns 1. For multipart, it returns the
 number of parts in the problem, not including psuedo-part 0. Thus,  number of parts in the problem, not including psuedo-part 0. 
 B<parts> may return an array with more parts in it then countParts  
 might lead you to believe.  
   
 =item * B<multipart>():  =item * B<multipart>():
   
 Returns true if the problem is multipart, false otherwise.  Returns true if the problem is multipart, false otherwise. Use this instead
   of countParts if all you want is multipart/not multipart.
   
 =item * B<responseType>($part):  =item * B<responseType>($part):
   
 Returns the response type of the part, without the word "response" on the  Returns the response type of the part, without the word "response" on the
 end. Example return values: 'string', 'essay', 'numeric', etc.  end. Example return values: 'string', 'essay', 'numeric', etc.
   
 =item * B<responseId>($part):  =item * B<responseIds>($part):
   
 Retreives the response ID for the given part, which may be an empty string.  Retreives the response IDs for the given part as an array reference containing
   strings naming the response IDs. This may be empty.
   
 =back  =back
   
Line 3281  sub responseType { Line 3280  sub responseType {
     return $self->{RESPONSE_TYPE}->{$part};      return $self->{RESPONSE_TYPE}->{$part};
 }  }
   
 sub responseId {  sub responseIds {
     my $self = shift;      my $self = shift;
     my $part = shift;      my $part = shift;
   
Removed from v.1.192  
changed lines
  Added in v.1.193

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